7.In one cycle, an engine burning a mixture of air and methanol (methyl alcohol) absorbs 525 J and expels 415 J. What is the engine’s efficiency?
To find the engine's efficiency, we can use the formula:
Efficiency = (Useful output energy / Input energy) x 100%
Given that the engine absorbs 525 J of energy and expels 415 J of energy, we can substitute these values into the formula:
Efficiency = (415 J / 525 J) x 100%
Now we can solve for efficiency:
Efficiency = (0.7905) x 100%
Efficiency ≈ 79.1%
Therefore, the engine's efficiency is approximately 79.1%.
To find the engine's efficiency, we need to use the formula for efficiency:
Efficiency = (Useful energy output / Total energy input) x 100
In this case, the useful energy output is the energy expelled by the engine, which is given as 415 J. The total energy input is the energy absorbed by the engine, which is given as 525 J.
Plugging in the values in the formula, we get:
Efficiency = (415 J / 525 J) x 100
To calculate this, divide 415 by 525, then multiply by 100:
Efficiency = (0.7905) x 100
Efficiency ≈ 79.05%
Therefore, the engine's efficiency is approximately 79.05%.
I am not sure what you mean by expel
If you mean does 415 J of work then
100 (415/525)
If you mean 415 was spewed out in the exhaust and
525 - 415 = 110 J was used to lift the load then
100 (110/525)