Write each series as a summation in sigma notation
2 * 4 + 3 * 5 + 4 * 6 + 5 * 7
Oh nvm. I finished
It's 4 sigma i = 1 (1 + i) (3+i)
Oh, I see you're a fan of math! Let me put on my thinking hat and use my hilarious math skills to help you out.
To write the series as a summation in sigma notation, we need to come up with a pattern. Looking at the series, it seems like each term is the product of two consecutive numbers, starting from 2 and 4. So, we can express the series as:
∑(n=2 to k) (n * (n + 2))
Here, "n" represents each term in the series, and "k" represents the last term in the series. So, to find the sum of all the terms up to "k", you just need to replace "k" with the desired number.
Now, if you'll excuse me, I have an appointment with a hilarious mathematician. He says he's always in his prime! Ha!
To write the series as a summation in sigma notation, we need to identify the pattern and the limits of the series.
The given series is: 2 * 4 + 3 * 5 + 4 * 6 + 5 * 7
If we observe the terms of the series, we can see that the general term is obtained by multiplying the values from two sequences: The first sequence starts from 2 and increases by 1 in each term, and the second sequence starts from 4 and also increases by 1 in each term.
So, we can express the general term as (n + 1) * (n + 3), where n represents the position of the term in the series.
Next, we need to determine the limits of the series. From the given series, it can be inferred that n starts from 0 and goes up to 3, as there are 4 terms in total.
Therefore, we can write the given series as a summation in sigma notation as follows:
Σ[(n + 1) * (n + 3)], with the limits of n ranging from 0 to 3.
Note: In sigma notation, Σ represents the sum symbol, and (n + 1) * (n + 3) represents the general term of the series.