A train is travelling with the velocity of 15m/s . It then accelerates at 0.5m/s^2 for 6 seconds . Calculate the velocity after the 6 seconds
a = .5 m/s^2
then
v = .5t + c m/s^2
when t = 0, v = 15
so 15 = .5(0) + c
c = 15
velocity = .5t + 15, when t = 6
velocity = .5(6) + 15 = ....
To calculate the velocity after 6 seconds, we need to use the formula for velocity with constant acceleration:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
Initial velocity (u) = 15 m/s
Acceleration (a) = 0.5 m/s^2
Time (t) = 6 seconds
Plugging the values into the formula:
v = 15 + 0.5 * 6
v = 15 + 3
v = 18 m/s
Therefore, the velocity of the train after the 6 seconds of acceleration is 18 m/s.
To calculate the velocity of the train after 6 seconds, we can use the following equation:
vf = vi + at
Where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
Given:
vi = 15 m/s (initial velocity)
a = 0.5 m/s^2 (acceleration)
t = 6 s (time)
Substituting the values into the equation, we get:
vf = 15 + (0.5 * 6)
= 15 + 3
= 18 m/s
Therefore, the velocity of the train after 6 seconds of acceleration is 18 m/s.