A gumball machine has 21 red gumballs, 24 yellow gumballs, and 15 blue gumballs. The gumballs are randomly mixed. What is the probability that the gumball machine dispenses a red gumball, then a yellow gumball as a percent to the nearest whole number?
Jenna is building a new apartment complex. The addresses are made up of a 3-digit number and a letter A through E. How many possible address combinations does Jenna have to work with while designing the complex?
21/60 for red, 24/59 for yellow
21/60 * 24/59 = ?
To find the probability of getting a red gumball followed by a yellow gumball, we need to know the total number of gumballs and the number of possible outcomes that satisfy the condition.
Total number of gumballs = 21 (red) + 24 (yellow) + 15 (blue) = 60
Since the gumballs are randomly mixed, the probability of selecting a red gumball as the first one is:
P(Red gumball) = Number of red gumballs / Total number of gumballs = 21 / 60
After taking out the first red gumball, the number of yellow gumballs becomes: 24 - 1 = 23.
The probability of selecting a yellow gumball as the second one is:
P(Yellow gumball) = Number of yellow gumballs / Remaining number of gumballs = 23 / 59
To find the probability of both events occurring, we multiply the two probabilities together:
P(Red gumball AND Yellow gumball) = P(Red gumball) * P(Yellow gumball) = (21/60) * (23/59)
To convert the probability to a percentage, we need to multiply the result by 100 and round it to the nearest whole number:
P(Red gumball, then Yellow gumball) = (21/60) * (23/59) * 100 ≈ 15%
So, the probability of the gumball machine dispensing a red gumball, then a yellow gumball is approximately 15%.