An airplane has a mass of 3.85 × 10^4kg and takes off under the influence of a constant net force of 2.13 × 10^4 N. What is the net force that acts on the plane's 74.4-kg pilot?
F = ma
So, what is a? The acceleration of the plane:
a = 2.13*10^4 / 3.85*10^4 = 0.55 m/s^2
so the net force on the pilot is 74.4*0.55 = 41.16N
I guess the "net force" does not include gravity, so add the pilot's weight to the above.
To find the net force acting on the plane's pilot, we need to consider the concept of Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a), or F = ma.
We already know the mass of the plane (3.85 × 10^4 kg) and the net force acting on it (2.13 × 10^4 N). However, we need to find the acceleration experienced by the pilot.
To find the acceleration, we can rearrange the formula F = ma to solve for a, which gives us a = F/m.
Now we can substitute the known values into the equation:
a = (2.13 × 10^4 N) / (74.4 kg)
a ≈ 286.29 m/s²
So, the acceleration experienced by the pilot is approximately 286.29 m/s².
Next, we can use Newton's second law to find the net force acting on the pilot. Now that we know the acceleration (a = 286.29 m/s²) and the mass of the pilot (74.4 kg), we can calculate the net force.
F = ma
F = (74.4 kg) × (286.29 m/s²)
F ≈ 2.13 × 10^4 N
Therefore, the net force acting on the plane's 74.4-kg pilot is approximately 2.13 × 10^4 N.