Integrate [0-2] √(3t^2)^2+(2-2t)^2dt
I'm assuming you meant
∫[0,2] √((3t^2)^2+(2-2t)^2) dt = 8.7891
You can do the integration by hand, but you need to remember the forms for inverse trig and hyperbolic functions.
∫[0,2] √((3t^2)^2+(2-2t)^2) dt = 8.7891
You can do the integration by hand, but you need to remember the forms for inverse trig and hyperbolic functions.