To begin the experiment, 1.65g of methane CH is burned in a bomb calorimeter
containing 1000 grams of water. The initial temperature of water is 18.98°C. The
specific heat of water is 4.184 J/g °C. The heat capacity of the calorimeter is 615
J/ °C. After the reaction the final temperature of the water is 36.38°C.
2. Calculate the change in temperature, AT. Show your work.
How would I even start this off?
Thanks
Note the methane is CH4 and not CH.
I'm a little confused about what you want. If you want the change in temperature of the water, it is 36.38 - 18.98 = ?
But there must be more to the problem and finding delta T for water.
yes. I am assuming you are trying to find the heat of combustion of CH4.
CH4 + O2 ==> CO2 + H2O + heat.
So the water absorbs heat and the calorimeter absorbs heat. The heat absorbed by the water is
q = mass H2O x specific heat H2O x delta T.