a ball of mass 4kg falls to the floor ; it lands with aspeed 6m/s.it.bounces off with the same speed.show that its momentum has changed by 48kgm/s.
momentum = mass * velocity
if up is +
then momentum before = -4*6 = -24
momentum after = +4*6 = + 24
after - before = 24 - -24 = 24+24 = 48
Active my mind
A ball of 4 kg falls to the floor it lands with Speed of 6 m/s it bounces off with the same speed show that its momentum has changed by 48 kg m/s
To show that the momentum has changed by 48 kg·m/s, we need to calculate the initial and final momentum of the ball.
Momentum (p) is calculated by multiplying the mass of an object (m) by its velocity (v):
p = m * v
Given data:
Mass of the ball, m = 4 kg
Initial velocity, v(initial) = 6 m/s
Final velocity, v(final) = -6 m/s (since the ball bounces off, the direction of velocity is reversed)
The initial momentum of the ball can be calculated as:
p(initial) = m * v(initial)
= 4 kg * 6 m/s
= 24 kg·m/s
The final momentum of the ball can be calculated as:
p(final) = m * v(final)
= 4 kg * -6 m/s
= -24 kg·m/s
To find the change in momentum, we subtract the initial momentum from the final momentum:
Change in momentum = p(final) - p(initial)
= (-24 kg·m/s) - (24 kg·m/s)
= -48 kg·m/s
Therefore, the change in momentum of the ball is -48 kg·m/s or 48 kg·m/s in the opposite direction.