It took George and Amy a total of 2 hours to put up all the notices for the pet show. They posted notices on trees and bulletin boards around town. All kinds of prizes were to be given, including one for the "ugliest" pet. Amy worked three times as long as George putting up signs. How long did each of them work?
with no algebra??
mmmhhh,
Amy worked 3 times as long as George.
That means if we have 4 units of time, then Amy gets 3 of those
and George only one
So split 2hours into 4 parts, which gives you 30 minutes.
So George works 30 minutes and Amy works 90 minutes
note 30 min + 90 min = 120 min = 2 hours
and 90 = 3*30
To find out how long each of them worked, we can use a system of equations. Let's assign variables to represent the time each person worked.
Let's say George worked for "x" hours, and Amy worked for "y" hours.
From the given information, we know that Amy worked three times as long as George, so we can write the equation:
y = 3x
We also know that it took them a total of 2 hours to put up all the notices, so we can write another equation:
x + y = 2
Now we have a system of two equations:
y = 3x
x + y = 2
We can solve this system by substitution or elimination.
Let's use substitution:
Substitute the value of "y" from the first equation into the second equation:
x + 3x = 2
4x = 2
x = 2/4
x = 0.5
Now that we know x, we can substitute it back into the first equation to find y:
y = 3(0.5)
y = 1.5
Therefore, George worked for 0.5 hours, and Amy worked for 1.5 hours.