Fence posts around a pasture are 2.5 m apart. A goat starts running west beside the fence. When it passes the fifth post, 9.0 s have elapsed. It passes the eleventh post at 11.5 s. What is the goat’s average velocity?
It would help if you proofread your questions before you posted them.
If the goat is starting at post #1, there is 2.5m * 4 to the 5th post = 10m.
Velocity = 10m/9s = ?
From 5th to 11th post = 2.5m * 6 = 15 m
Velocity = 15m/11.5s = ??
Average velocity = (? + ??)/2 = ???