A balloon contains 7.2L of He.The pressure is reduced to 2.00atm and the balloon expands to occupy a volume of 25.1L.What is the intial pressure exerted on the balloon? show working out
To find the initial pressure exerted on the balloon, we can make use of Boyle's law, which states that the product of the initial volume and pressure of a given amount of gas is equal to the product of the final volume and pressure.
Mathematically, Boyle's law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure of the gas
V1 = Initial volume of the gas
P2 = Final pressure of the gas
V2 = Final volume of the gas
In this case, we are given the initial volume (V1 = 7.2L), final volume (V2 = 25.1L), and final pressure (P2 = 2.00 atm). We need to solve for the initial pressure (P1).
Using the formula, we can rearrange it to solve for P1:
P1 = (P2 * V2) / V1
Substituting the given values:
P1 = (2.00 atm * 25.1L) / 7.2L
P1 = 50.2 atm * L / 7.2L
P1 ≈ 6.97 atm
Therefore, the initial pressure exerted on the balloon is approximately 6.97 atm.
Use P1V1 = P2V2
Substitute the numbers and solve for P1.