a rectangular pyramid that measures 10cm by 7cm has a height of 11cm. Cal,side of the triangle
divide that rectangular base, corners A, B, C, D into 4 rectangles each 5 by 3.5, call the center Q.
now QB for example is sqrt (25 + 12.25) = sqrt (37.25) = 6.10
call the top T
QT = 11 so the side of the triangle at the corner, TB = sqrt(11^2 + 37.25)
so TB = 12.6
I need explicit answer of the question
Hey there! Did you know that pyramids were quite fashionable in ancient Egypt? But enough about that, let's calculate the side of the triangle on this rectangular pyramid!
To find the side of the triangle, we can use the Pythagorean theorem. The triangle in question is a right triangle formed by the height of the pyramid and two sides of the base.
So, using the Pythagorean theorem:
Side² = (10/2)² + 7²
Side² = 5² + 7²
Side² = 25 + 49
Side² = 74
Taking the square root of both sides, we find:
Side ≈ √74
Now, I'd love to give you an exact answer, but my calculator only tells jokes. So, instead, let's round that to the nearest whole number:
Side ≈ 9 cm
So, the side of the triangle on this rectangular pyramid is approximately 9 cm. Voila!
To find the side of the triangular base of the rectangular pyramid, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, the rectangular pyramid has a base that measures 10cm by 7cm, which forms a right-angled triangle with the height of the pyramid.
Let's call the side of the triangle we are trying to find "x". So we have a right-angled triangle with sides 10, 7, and x. The equation can be written as:
x^2 = 10^2 + 7^2
Simplifying this equation:
x^2 = 100 + 49
x^2 = 149
To find "x", we take the square root of both sides of the equation:
x = √149
Using a calculator, the value of √149 is approximately 12.206.
Therefore, the side of the triangular base of the rectangular pyramid is approximately 12.206 cm.
To find the side length of the triangle in a rectangular pyramid, we first need to identify the base of the pyramid. In this case, the base is a rectangle with dimensions 10cm by 7cm.
The base of a rectangular pyramid is a rectangle, so the triangles that make up the sides of the pyramid are right triangles. We can use the Pythagorean theorem to find the length of the side of the triangle.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In a right triangle, the height of the triangle is one of the legs, and the side length of the rectangle is the other leg. So, we have:
Height (leg) = 11 cm
Base (leg) = 7 cm
We want to find the length of the hypotenuse (the side length of the triangle).
Using the Pythagorean theorem, we can write the equation:
hypotenuse^2 = height^2 + base^2
Substituting the known values:
hypotenuse^2 = 11^2 + 7^2
hypotenuse^2 = 121 + 49
hypotenuse^2 = 170
To find the length of the hypotenuse, we can take the square root of both sides:
hypotenuse = √170
hypotenuse ≈ 13.04 cm
Therefore, the side length of the triangle is approximately 13.04 cm.