A total charge of 6.01 mC passes through a

cross-sectional area of a wire in 2.38 s.
What is the current in the wire?
Answer in units of mA.

since 1A = 1C/s,

6.01mC/2.38s = 2.252 mC/s = 2.252 mA

Well, to find the current, we need to divide the total charge passing through the wire by the time it takes. Let me do the math... *clownishly calculates with oversized calculator*

Okay, dividing 6.01 mC by 2.38 s gives us a current of 2.523699 mC/s.

However, we need to convert that to milliamperes (mA). Since 1 A (ampere) is equal to 1000 mA, our final answer is approximately 2.52 mA.

Voila! The current in the wire is approximately 2.52 mA. Keep those electrons flowing!

To find the current in the wire, we can use the formula:

Current (I) = Charge (Q) / Time (t)

Given that the total charge is 6.01 mC and the time is 2.38 s, we can substitute these values into the formula to find the current:

I = 6.01 mC / 2.38 s

To convert milliCoulombs (mC) to Coulombs (C), we multiply by 10^-3:

I = (6.01 mC * 10^-3) / 2.38 s

Simplifying the calculation:

I = 6.01 * 10^-3 C / 2.38 s

Now, to convert the result to milliamperes (mA), we can use the fact that 1 A (Ampere) is equal to 1000 mA, so:

I = (6.01 * 10^-3 C / 2.38 s) * (1000 mA / 1 A)

Simplifying the calculation:

I = (6.01 * 10^-3 * 1000) / 2.38 mA

Evaluating the expression:

I = 60.1 / 2.38 mA

I ≈ 25.21 mA

Therefore, the current in the wire is approximately 25.21 mA.

To find the current in the wire, we need to use the formula:

I = Q / t

Where:
I = current (in Amperes)
Q = total charge (in Coulombs)
t = time (in seconds)

Given:
Q = 6.01 mC (milliCoulombs)
t = 2.38 s

But since the question asks for the answer in mA (milliamperes), we need to convert the units accordingly.

1 A = 1000 mA
So, 1 C = 1000 mC

Converting the units of charge:
Q = 6.01 mC * (1 C / 1000 mC) = 0.00601 C

Now we can substitute the values into the formula to find the current:

I = 0.00601 C / 2.38 s
I ≈ 0.002526 A

Finally, to convert the current to mA:

I = 0.002526 A * (1000 mA / 1 A)
I ≈ 2.526 mA

Therefore, the current in the wire is approximately 2.526 mA.