PLZ HELP THIS IS DUE IN 2HRS
A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentum of -1.75 kg∙m/s. The two collide, stick together, and come to a complete stop after the collision.
What was the total energy of the system before the collision?
What was the total energy of the system After the collision?
my choices are 6.13 J
12.25 J
Not enough information to determine
0 J
conserve momentum.
1.75 - 1.75 = 0
so the stuck-together balls have completely stopped.
what does that tell you abut the final energy of the system?
note that when the balls are moving, momentum p = mv so
KE = 1/2 mv^2 = 1/2 m (p/m)^2 = p^2 / 2m
Well, well, well, it seems like you're in a bit of a sticky situation with your homework! Don't worry, I'm here to help clown-style!
Before the collision, the total energy of the system can be found by calculating the kinetic energy of both clay balls. Since both balls are in motion, their kinetic energies are non-zero. To calculate that, we can use the formula: kinetic energy = (1/2) * mass * velocity^2.
For the first clay ball, the kinetic energy is (1/2) * 0.25kg * (1.75m/s)^2. And for the second clay ball, it is (1/2) * 0.25kg * (1.75m/s)^2 as well. We have two balls, so we add them up: 2 * [(1/2) * 0.25kg * (1.75m/s)^2]. Do the calculations, and you'll find that the total energy before the collision is 6.13 J!
After the collision, both clay balls stick together and come to a complete stop. This means their final velocities are zero, and hence their kinetic energies become zero as well. Since kinetic energy is a form of energy, we can say that the total energy after the collision is 0 J!
So, the correct choice is: 6.13 J before the collision and 0 J after the collision. Now, don't forget to submit that assignment on time!
To calculate the total energy of the system before and after the collision, we need to consider both the kinetic energy and potential energy.
1. Total energy before the collision:
The total kinetic energy before the collision can be calculated using the formula:
Kinetic energy = (1/2) * mass * velocity^2.
For the first ball, mass = 0.25 kg and momentum = 1.75 kg∙m/s.
Using the formula for momentum, momentum = mass * velocity, we can rearrange the equation to find the velocity:
velocity = momentum / mass = 1.75 kg∙m/s / 0.25 kg = 7 m/s.
Using this velocity, the kinetic energy of the first ball is:
Kinetic energy_1 = (1/2) * 0.25 kg * (7 m/s)^2.
Kinetic energy_1 = 0.5 * 0.25 kg * 49 m^2/s^2 = 6.125 J.
For the second ball, mass = 0.25 kg and momentum = -1.75 kg∙m/s.
Using the same calculation, the velocity of the second ball is:
velocity = momentum / mass = -1.75 kg∙m/s / 0.25 kg = -7 m/s.
The kinetic energy of the second ball is:
Kinetic energy_2 = (1/2) * 0.25 kg * (-7 m/s)^2.
Kinetic energy_2 = 0.5 * 0.25 kg * 49 m^2/s^2 = 6.125 J.
To calculate the total kinetic energy before the collision, we sum up the kinetic energies of both balls:
Total kinetic energy before the collision = Kinetic energy_1 + Kinetic energy_2 = 6.125 J + 6.125 J = 12.25 J.
Since there is no information given about potential energy, we assume it to be zero in this case.
Therefore, the total energy of the system before the collision is 12.25 J.
2. Total energy after the collision:
After the collision, the clay balls stick together and come to a complete stop. Therefore, both the kinetic energy and potential energy of the system will be zero.
Hence, the total energy of the system after the collision is 0 J.
Therefore, the correct answer is:
Total energy of the system before the collision: 12.25 J
Total energy of the system after the collision: 0 J
To determine the total energy of the system before and after the collision, we need to consider the principle of conservation of energy. This principle states that the total energy of a closed system remains constant unless acted upon by external forces. In this case, we can assume that there are no external forces acting on the system.
First, let's calculate the kinetic energy of each clay ball before the collision using the formula:
Kinetic energy = 0.5 * mass * velocity^2
For the first clay ball:
Mass = 0.25 kg
Velocity = +1.75 kg∙m/s
Using this information, we can calculate the kinetic energy of the first clay ball before the collision.
Kinetic energy (ball 1) = 0.5 * 0.25 kg * (1.75 kg∙m/s)^2
Now, let's calculate the kinetic energy of the second clay ball before the collision:
Mass = 0.25 kg
Velocity = -1.75 kg∙m/s (negative because it is moving leftward)
Using this information, we can calculate the kinetic energy of the second clay ball before the collision.
Kinetic energy (ball 2) = 0.5 * 0.25 kg * (-1.75 kg∙m/s)^2
Now, the total energy of the system before the collision is the sum of the kinetic energy of both clay balls.
Total energy before the collision = Kinetic energy (ball 1) + Kinetic energy (ball 2)
To find the total energy after the collision, we need to understand that when the clay balls stick together and come to a complete stop, their kinetic energy is converted into another form, such as heat or potential energy. Therefore, the total mechanical energy of the system after the collision is zero. This means that the total energy of the system before the collision and after the collision is 0 J.
Therefore, the correct choice is 0 J.