100-(5x(3+4)
did you just answer your own question?
yes, and he got it wrong, both syntactically and computationally.
Is x a variable if not this is how the problem should look like this:
100 - [5 x (3 + 4)]
oobleck can you please answer my question?
If x is a variable, it should be written as
100 - [5x (3 + 4)]
100 - 5x(7)
100 - 35x
the answer is 65
100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)] 100-[5X(3+4)]100−[5×(3+4)]V 100-[5X(3+4)]100−[5×(3+4)]
To solve the expression 100-(5x(3+4)), we need to follow the order of operations, also known as PEMDAS:
1. Parentheses: Evaluate the expression inside the parentheses first.
In this case, (3+4) equals 7.
So the expression becomes 100-(5x7).
2. Multiplication: Perform any multiplication next.
5 multiplied by 7 equals 35.
The expression becomes 100-35.
3. Subtraction: Finally, perform the subtraction operation.
100 minus 35 is equal to 65.
Therefore, the value of the expression 100-(5x(3+4)) is 65.