If the linear expansivity of a copper rod is 1.7*10^_5_k^_1, calculate the expansion 10m of copper 50 of when heated from 10decreecentury to 80decreecentury
I do not know what your century is about
change in length = length * your coefficient of expansion * change in temperature
To calculate the expansion of a copper rod, we can use the formula:
ΔL = α * L * ΔT
Where:
ΔL is the change in length of the copper rod
α is the linear expansivity coefficient of copper
L is the original length of the copper rod
ΔT is the change in temperature
Given:
α = 1.7 × 10^-5 K^-1
L = 10 m
ΔT = 80 °C - 10 °C = 70 °C
Plugging in the values, we can calculate the expansion:
ΔL = (1.7 × 10^-5 K^-1) * (10 m) * (70 °C)
ΔL = 1.7 × 10^-4 m/K * 10 m * 70 °C
ΔL = 1.7 × 10^-3 m/K * 7
ΔL = 1.19 × 10^-2 m
Therefore, the expansion of a 10 m copper rod, heated from 10 °C to 80 °C, is approximately 1.19 × 10^-2 meters.
To calculate the expansion of the copper rod, we can use the formula:
ΔL = α * L0 * ΔT
Where:
ΔL is the change in the length of the rod
α is the linear expansivity of copper
L0 is the original length of the rod
ΔT is the change in temperature
Given:
α (linear expansivity of copper) = 1.7 × 10^-5 K^-1
L0 (original length of the rod) = 10 m
ΔT (change in temperature) = 80 °C - 10 °C = 70 °C
Now, let's substitute the given values into the formula:
ΔL = (1.7 × 10^-5 K^-1) * (10 m) * (70 °C)
Calculating the above expression gives us:
ΔL = 1.19 × 10^-2 m
Therefore, the expansion of the copper rod when heated from 10 °C to 80 °C is 0.0119 meters (or 11.9 millimeters).