On Wednesday, a local hamburger shop sold a combined total of 544 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Wednesday?
h = numbers of hamburgers
c = numbers of cheeseburgers
The number of cheeseburgers sold was three times the number of hamburgers sold means:
c = 3 h
A local hamburger shop sold a combined total of 544 hamburgers and cheeseburgers means:
h + c = 544
h + 3 h = 544
4 h = 544
h = 544 / 4
h = 136
Let's suppose the number of hamburgers sold is "x".
According to the given information, the number of cheeseburgers sold is three times the number of hamburgers sold.
Therefore, the number of cheeseburgers sold is 3*x.
The combined total of hamburgers and cheeseburgers sold is 544.
So, we can write the equation: x + 3*x = 544.
Simplifying the equation, we have: 4*x = 544.
Dividing both sides by 4, we find: x = 544/4.
Evaluating the expression, we get: x = 136.
Therefore, 136 hamburgers were sold on Wednesday.
To find the number of hamburgers sold on Wednesday, we need to set up some equations based on the given information.
Let's assume the number of hamburgers sold is represented by 'H', and the number of cheeseburgers sold is represented by 'C'.
We are given two pieces of information:
1) The total number of hamburgers and cheeseburgers sold is 544.
We can write this as an equation: H + C = 544.
2) The number of cheeseburgers sold is three times the number of hamburgers sold.
We can write this as an equation: C = 3H.
Now we have a system of two equations. We can solve this system using substitution or elimination.
Let's solve it using substitution:
Substitute the value of C from the second equation into the first equation:
H + 3H = 544
4H = 544
Divide both sides by 4 to solve for H:
H = 544 / 4
H = 136
Therefore, the number of hamburgers sold on Wednesday is 136.