For the reaction 2Na + 2H2O -> 2NaOH + H2, how many grams of hydrogen are produced if there are 48 g of sodium
if you can show me with work that would be amazing :)
Sure! To determine the amount of hydrogen gas produced, we need to use stoichiometry.
First, we need to determine the molar mass of sodium (Na) and hydrogen (H2). The molar mass of sodium is 22.99 g/mol, and hydrogen has a molar mass of 2.02 g/mol.
Next, we need to calculate the number of moles of sodium (Na) using the given mass of 48 g and the molar mass of sodium. We can use the formula:
Number of moles = Mass / Molar mass
Number of moles of Na = 48 g / 22.99 g/mol
Number of moles of Na = 2.086 mol (rounded to three decimal places)
According to the balanced equation, 2 moles of sodium (Na) react to produce 1 mole of hydrogen gas (H2). Therefore, we can set up a ratio using the coefficients of the balanced equation:
2 moles of Na / 1 mole of H2
Using this ratio, we can find the number of moles of hydrogen gas produced:
Number of moles of H2 = Number of moles of Na × (1 mole of H2 / 2 moles of Na)
Number of moles of H2 = 2.086 mol × 1/2
Number of moles of H2 = 1.043 mol (rounded to three decimal places)
Finally, we can calculate the mass of hydrogen gas produced using the molar mass of hydrogen:
Mass of H2 = Number of moles of H2 × Molar mass of H2
Mass of H2 = 1.043 mol × 2.02 g/mol
Mass of H2 = 2.108 g (rounded to three decimal places)
Therefore, approximately 2.108 grams of hydrogen gas are produced when there are 48 grams of sodium.
how many moles of Na in 48g?
The equation says you will half that many moles of H2
So, how many grams is that?