If the expressed mass of AlCl³ to be formed is 3.5 g, what should be the initial mass of the pure aluminum metal
molar mass of AlCl₃ is 133 g
molar mass of Al is 27 g
3.5 g * (27 / 133) = ?
0.71 g Al
Thank you
To determine the initial mass of pure aluminum metal required to form a given mass of AlCl₃, we need to use the concept of stoichiometry.
1. Write the balanced chemical equation for the reaction:
2 Al + 3 Cl₂ → 2 AlCl₃
2. Determine the molar mass of AlCl₃:
AlCl₃ = (1 Al × atomic mass of Al) + (3 Cl × atomic mass of Cl)
You can find the atomic masses of Al and Cl on the periodic table.
3. Convert the given mass of AlCl₃ to moles:
Moles = mass / molar mass
Moles of AlCl₃ = 3.5 g / molar mass of AlCl₃
4. Use the stoichiometry of the balanced equation to determine the moles of aluminum needed:
From the balanced equation, we see that 2 moles of Al react to form 2 moles of AlCl₃.
Therefore, moles of Al = 2 × moles of AlCl₃
5. Convert moles of aluminum to mass:
Mass of aluminum = moles of Al × molar mass of Al
By following these steps, you can calculate the initial mass of pure aluminum metal needed to form a given mass of AlCl₃. Make sure to use the molar masses of aluminum and aluminum chloride accurately to obtain precise results.