2 jugs and 10 cups can hold 3,600 ml of water. Given that a cup can hold 1/4 as much water as a jug, how much water can a jug hold? Give your answer in liters.
2 J + 10 * J/4 = 3.600 liters
2 J + 2.5 J = 3.6
J = 3.6 /4.5 = 0.8 Liter
Let's assume the capacity of a jug as "x" liters.
According to the given information, a cup can hold 1/4 as much water as a jug. Therefore, the capacity of a cup is (1/4)x liters.
There are 2 jugs and 10 cups in total. So, the total volume of water they can hold is:
2(x liters) + 10((1/4)x liters) = 3,600 ml
Simplifying the equation:
2x + 10(1/4)x = 3,600
Expanding:
2x + (10/4)x = 3,600
Combining like terms:
(8/4)x + (10/4)x = 3,600
(18/4)x = 3,600
Multiplying both sides by (4/18) to solve for x:
x = (3,600 * 4) / 18
x ≈ 800
Therefore, a jug can hold approximately 800 liters of water.
To find out how much water a jug can hold, let's start by converting the given information into a common unit.
We are given that 2 jugs and 10 cups together can hold 3,600 ml of water. Let's consider the volume of water held by the jugs and cups separately.
Let's assume that the volume of water a jug can hold is represented by J ml. Since a cup can hold 1/4 as much water as a jug, the volume of water held by a cup is (1/4)J ml.
Now, let's express the volume of water held by the jugs and cups in terms of J.
The volume of water held by the 2 jugs is 2J ml.
The volume of water held by the 10 cups is 10 * (1/4)J = (5/2)J ml.
According to the given information, the total volume of water held by the jugs and cups is 3,600 ml. So, we can write the equation:
2J + (5/2)J = 3600
To solve for J, we can combine like terms:
(4/2)J + (5/2)J = 3600
(9/2)J = 3600
Now, we can isolate J by multiplying both sides of the equation by 2/9:
J = (3600 * 2) / 9
J = 800 ml
Since the question asks for the volume in liters, let's convert J from milliliters to liters:
1 liter = 1000 milliliters
So, J = 800 / 1000 = 0.8 liters.
Therefore, a jug can hold 0.8 liters of water.