Calvin has 30 colorful erasers. Jay has 45 such erasers. How many colorful erasers must Jay give Calvin so that the number of colorful erasers Calvin has is twice that of Jay?
30 + n = 2 (45 - n) = 90 - 2n
3 n = 60
Let's denote the number of erasers Jay gives to Calvin as 'x'.
Initially, Calvin has 30 colorful erasers and Jay has 45 colorful erasers.
After Jay gives 'x' erasers to Calvin, Calvin will have 30 + x erasers.
And Jay will have 45 - x erasers.
According to the question, Calvin's erasers will be twice that of Jay's erasers.
So, we can write the equation:
30 + x = 2(45 - x)
Let's solve the equation to find the value of 'x'.
30 + x = 90 - 2x
Adding 2x to both sides:
3x + x = 90 - 30
Combining like terms:
4x = 60
Dividing both sides by 4:
x = 60/4
x = 15
Therefore, Jay must give Calvin 15 colorful erasers so that the number of colorful erasers Calvin has is twice that of Jay's.
To solve this problem, we need to find out how many erasers Jay needs to give Calvin in order for Calvin to have twice the number of erasers as Jay.
Let's start by finding out how many erasers Calvin currently has.
Calvin has 30 colorful erasers.
Next, let's find out how many erasers Jay currently has.
Jay has 45 colorful erasers.
Now, let's represent the number of erasers Jay needs to give Calvin as x.
Calvin's new number of erasers = Calvin's current number + x
Jay's new number of erasers = Jay's current number - x
According to the problem, Calvin's new number of erasers is twice that of Jay's new number of erasers. Therefore, we can write the equation:
Calvin's new number of erasers = 2 * Jay's new number of erasers
Substituting the values we already have, we can write the equation:
30 + x = 2 * (45 - x)
Now, we can solve this equation to find the value of x.
30 + x = 90 - 2x [Distribute 2 to both terms inside the parentheses]
3x = 60 [Combine like terms]
x = 20 [Divide both sides by 3]
Therefore, Jay needs to give Calvin 20 colorful erasers so that Calvin has twice as many erasers as Jay.