There are 100 adults and children together. An adult could consume 3 buns while 3 children could only finish one bun. If 100 buns were consumed, how many adults were there?
No, I am not going to do them all for you
adult eats 3
child eats 1/3
then the same way as the last problem.
To solve this problem, we can set up equations based on the given information.
Let's assume the number of adults be A and the number of children be C.
According to the given information:
1. An adult consumes 3 buns, so the total number of buns consumed by adults would be 3A.
2. Three children can consume one bun each, so the total number of buns consumed by children would be 3C.
From the problem statement, we know that the total number of buns consumed is 100. Therefore, we can write the equation:
3A + 3C = 100
Since we are asked to find the number of adults (A), we need to eliminate the C variable from the equation. We can do this by using the fact that there are 100 adults and children together:
A + C = 100
To eliminate C, we can solve this equation for C as:
C = 100 - A
Now substituting this into the first equation:
3A + 3(100 - A) = 100
Simplifying the equation:
3A + 300 - 3A = 100
300 = 100
This equation cannot be true, which means there is no solution that satisfies the given conditions. There must be a mistake in the problem statement or a contradiction in the information provided.