How many grams of O2 will be formed from 3.76 g of KClO3?
To determine the number of grams of O2 formed from 3.76 g of KClO3, you need to use stoichiometry, which relates the number of moles of one substance to another in a balanced chemical equation.
Step 1: Write the balanced chemical equation for the reaction.
2 KClO3 → 2 KCl + 3 O2
Step 2: Calculate the molar mass of KClO3 and O2.
The molar mass of KClO3 is:
K = 39.10 g/mol
Cl = 35.45 g/mol
O = 16.00 g/mol
Molar mass of KClO3 = 39.10 + 35.45 + (3 x 16.00) = 122.55 g/mol
The molar mass of O2 is:
O = 16.00 g/mol
Molar mass of O2 = (2 x 16.00) = 32.00 g/mol
Step 3: Calculate the number of moles of KClO3.
molar mass of KClO3 = 122.55 g/mol
mass of KClO3 = 3.76 g
moles of KClO3 = mass of KClO3 / molar mass of KClO3
Step 4: Use the stoichiometry of the balanced equation to determine the moles of O2 produced.
According to the balanced equation, 2 moles of KClO3 produce 3 moles of O2.
So, moles of O2 = moles of KClO3 x (3 moles of O2 / 2 moles of KClO3)
Step 5: Calculate the mass of O2.
mass of O2 = moles of O2 x molar mass of O2
Now, let's perform the calculations:
mass of KClO3 = 3.76 g
molar mass of KClO3 = 122.55 g/mol
moles of KClO3 = 3.76 g / 122.55 g/mol ≈ 0.0307 mol
moles of O2 = 0.0307 mol x (3 mol O2 / 2 mol KClO3) ≈ 0.0461 mol
mass of O2 = 0.0461 mol x 32.00 g/mol ≈ 1.47 g
Therefore, approximately 1.47 grams of O2 will be formed from 3.76 grams of KClO3.
write the balanced reaction equation.
How many moles of O2 do you get for a mole of KClO3?
how many moles of KClO3 are in 3.76 grams?
Now finish it off.