Triangle abc has coordinates of a(-8,-8) b(4,-2) and c(2,2) find the coordinates of its image after a dilation centered at the origin with a scale factor of 1.5
A(-12,-12) B(6,-3) C(3,3)
A(-5.33,-5.33) B(2.67,-1.33) C(1.33,1.33)
A(-12,-8) B(6,-2) C(3,2)
A(-8,-8) B(4,-2) C(2,2)
I’m not looking for answers I just need someone to explain this to me because I have no clue what to do
since the origin is the center of dilation, it's easy. Just multiply all the coordinates by 1.5
Since they are all even numbers, there will be no fractions in the answer.
Would the answer be A?
correct
To find the coordinates of the image of triangle ABC after a dilation centered at the origin with a scale factor of 1.5, you need to multiply the coordinates of each vertex by the scale factor.
Given that the scale factor is 1.5, you can multiply the x and y coordinates of each vertex by 1.5 to determine the new coordinates.
Let's go through each vertex of the triangle:
Vertex A: (-8, -8)
Multiply the x-coordinate by 1.5: -8 * 1.5 = -12
Multiply the y-coordinate by 1.5: -8 * 1.5 = -12
Therefore, the image of point A is (-12, -12).
Vertex B: (4, -2)
Multiply the x-coordinate by 1.5: 4 * 1.5 = 6
Multiply the y-coordinate by 1.5: -2 * 1.5 = -3
Therefore, the image of point B is (6, -3).
Vertex C: (2, 2)
Multiply the x-coordinate by 1.5: 2 * 1.5 = 3
Multiply the y-coordinate by 1.5: 2 * 1.5 = 3
Therefore, the image of point C is (3, 3).
Hence, the coordinates of the triangle ABC after the dilation are:
A(-12, -12), B(6, -3), and C(3, 3).