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What is the set of quantum numbers for the last three electrons in an iodine atom?

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Oobleck plz help

  1. Electron configuration for I is
    It would be so much easier to do this if I could draw a diagram.
    [Kr] 4d10 5s2 5p5 so the last 5p level will be
    n will be 5
    the p level is "ell" (or l) = 1
    ml = -1 or 0 or +1
    ms = + 1/2 or - 1/2
    First electron in the p level will have ml = -1 and ms = +1/2
    Second electron in the p level will have ml = 0 and ms = +1/2
    Third electron in the p level will have ml = +1 and ms = +1/2
    Fourth electron in the p level will have ml = -1 and ms = -1/2
    Fifth electron in the p level will have ml = 0 and ms = -1/2
    So the last three electrons in my description will be labeled Fifth, fourth, third above.
    Hope this is not too convoluted to understand.

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    DrBob222

  2. Wow what a brainiac

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    eddly puzzle

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