The sum of ages of Sarpong and Quartey is 50years.in five years time the age of Quartey will be four times the agf of Sarpong now.how old is each boy. the equation for the word problem
Yes
S + Q = 50
Q + 5 = 4 S
It's good that you have this problem on the page and so I say bravos but you must solve it systematically
To find the ages of Sarpong and Quartey, we can create a system of equations based on the given information.
Let S be Sarpong's current age and Q be Quartey's current age.
From the first statement, we know that S + Q = 50.
From the second statement, we know that in five years, Quartey's age (Q + 5) will be four times Sarpong's current age (S).
Therefore, we have the second equation: Q + 5 = 4S.
Solving this system of equations will give us the ages of Sarpong and Quartey.
We can start by substituting the value of Q from the second equation into the first equation:
S + (4S - 5) = 50
Combining like terms:
5S - 5 = 50
Adding 5 to both sides:
5S = 55
Dividing both sides by 5:
S = 11
Now, substituting the value of S into the second equation:
Q + 5 = 4(11)
Q + 5 = 44
Subtracting 5 from both sides:
Q = 39
Therefore, Sarpong is 11 years old and Quartey is 39 years old.