Language Arts 7 B Unit 6: Language and Style Help
I go to connexus and and literaly 2 years and 4 days later Nobody is still correct
do the word problem on your own
The spinner has a total of 8 sections, out of which 2 are red. The experimental probability of the spinner landing on red is the number of times red was spun divided by the total number of spins:
Experimental probability of landing on red = 2 / (6 + 4 + 3 + 5) = 2 / 18 = 1 / 9
The fraction is 1 over 9. None of the given answer choices matches with this, so we need to select the closest option.
The nearest option to 1/9 is "the fraction is 1 over 4." However, this is not accurate. The experimental probability is less than one-fourth. The best option is therefore:
Answer: B. one-third.
A spinner is shown with two blue, two green, two yellow, and two red sections. The arrows is pointing to a red section. Color
red
blue
green
yellow
# of times spun
6
4
3
5
Use the table to answer the question.
What is the experimental probability of the spinner landing on blue?
A. Start Fraction 2 over 7 End Fraction
B. one-fourth
C. start fraction 2 over 9 end fraction
The spinner has a total of 8 sections, out of which 2 are blue. The experimental probability of the spinner landing on blue is the number of times blue was spun divided by the total number of spins:
Experimental probability of landing on blue = 2 / (6 + 4 + 3 + 5) = 2 / 18 = 1 / 9
Answer: C. start fraction 2 over 9 end fraction.
Two coins were tossed 10 times. The results are shown in the table.
Toss 1 2 3 4 5 6 7 8 9 10
Result HH TT HT TH HT HH TH TT TH HT
Use the table and information to answer the question.
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A. 0.8
B. 0.2
C. 0.6
3 / 8
2 of 8 Answered
In each coin toss, there are two possible outcomes - heads (H) or tails (T). So, the probability of getting tails in one toss is 1/2, and the probability of getting heads is also 1/2.
To find the probability that at least one of the coins landed on heads, we can find the complement of the probability that both coins landed on tails (i.e., both coins landed on tails in all 10 tosses).
The probability that both coins landed on tails in one toss is 1/2 x 1/2 = 1/4. So, the probability that both coins landed on tails in all 10 tosses is (1/4)^10 = 1/2,56,00,000.
Therefore, the probability that at least one of the coins landed on heads is 1 - probability that both coins landed on tails in all 10 tosses = 1 - 1/2,56,00,000 ≈ 1. Hence, the answer is:
Answer: A. 0.8 (expressed as a decimal).
Two coins were tossed 10 times. The results are shown in the table below.
Toss 1 2 3 4 5 6 7 8 9 10
Result HH TT HT TH HT HH TH TT TH HT
Use the table and information to answer the question.
What is the experimental probability that both of the coins landed on tails? Express the probability as a decimal.
A. 0.8
B. 0.2
C. 0.6
4 / 8
3 of 8 Answered
In each coin toss, there are two possible outcomes - heads (H) or tails (T). So, the probability of getting tails in one toss is 1/2, and the probability of getting heads is also 1/2.
To find the probability that both coins landed on tails in one toss, we need to multiply the probability of getting tails on the first coin toss with the probability of getting tails on the second coin toss.
The probability that both coins landed on tails in one toss is 1/2 x 1/2 = 1/4.
Since the coins were tossed 10 times, we need to multiply this probability with itself 10 times to find the probability of both coins landing on tails in all 10 tosses:
Probability of both coins landing on tails in all 10 tosses = (1/4)^10 = 1/2,56,00,000 (approximately).
Therefore, the experimental probability that both coins landed on tails is:
Answer: B. 0.2 (expressed as a decimal).
A survey of a random sample of 20 moviegoers shows that 8 people purchased popcorn to eat while watching the movie. If a theater has 80 people in it, how many should you expect to have purchased popcorn?
A. 40 people
B. 36 people
C. 32 people