A basket contains 3 red balls 5 blue balls and 7 green ball 2 balls are picked one after the other without replacement find the probablity that first is red and second is blue
I dnt know it
3/15 × 4/14
12/210
2/35 ✓
To find the probability that the first ball drawn is red and the second ball drawn is blue, we need to consider the number of favorable outcomes and the number of possible outcomes.
The number of favorable outcomes is the number of ways we can draw a red ball followed by a blue ball.
Since there are 3 red balls and 5 blue balls in the basket, the number of favorable outcomes is 3 (for selecting a red ball) multiplied by 5 (for selecting a blue ball after the red ball is drawn).
The number of possible outcomes is the total number of balls in the basket.
In this case, there are 3 red balls, 5 blue balls, and 7 green balls, giving a total of 3 + 5 + 7 = 15 balls.
Therefore, the probability of drawing a red ball first and a blue ball second can be calculated by dividing the number of favorable outcomes by the number of possible outcomes:
Probability = (Number of favorable outcomes) / (Number of possible outcomes)
= (3 * 5) / 15
= 15 / 15
= 1
So, the probability of drawing a red ball first and a blue ball second without replacement is 1, which means it is guaranteed to happen.
probab(red, then blue) = 3/15 * 5/14
= 15/210
= 1/14