Calculate the volume of conc .Hcl required for preparing 250ml 0.1M?
The concentration of commercial HCl is considered to be 12 M. I think it is more like 11.6 M but use either number you wish depending upon your definition of concentration of HCl. Then
mLa x Ma = mLb x Mb
mLa x 12 = 250 x 0.1
Solve for mLa. Than pipet that amount of concentration HCl into a 250 mL volumetric flask, add some distilled water to the flask, swirl somewhat, add distilled water to the mark on the volumetric flask, stopper, mix thoroughly, label.
To calculate the volume of concentrated hydrochloric acid (HCl) required to prepare a 250ml solution with a concentration of 0.1M, you will need to use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration (the concentration of the concentrated HCl)
V1 = volume of concentrated HCl
C2 = final concentration (the desired concentration of the solution)
V2 = final volume (the volume of the solution you want to prepare)
In this case, you want to prepare a solution with a final volume of 250ml (V2) and a final concentration of 0.1M (C2).
Now, you need to know the concentration of the concentrated hydrochloric acid. Let's assume it has a concentration of 37% (which is a commonly available concentration for concentrated HCl).
First, convert the final concentration (0.1M) into moles per liter (mol/L) by multiplying by the final volume (250ml) converted into liters (0.250L):
C2 = 0.1 mol/L * 0.250 L = 0.025 mol
Next, rearrange the formula to solve for V1 (volume of concentrated HCl):
V1 = (C2 * V2) / C1
Using the given concentration (37%) for the concentrated HCl (C1), substitute the values into the equation:
V1 = (0.025 mol * 0.250 L) / 0.37 mol/L = 0.0169 L
Finally, convert the volume from liters to milliliters:
V1 = 0.0169 L * 1000 ml/L = 16.9 ml
Therefore, you will need approximately 16.9 ml of concentrated HCl to prepare a 250ml solution with a concentration of 0.1M.