A paticle executing simple harmonin motion have frequency 50hz and an armputide 8-0*10'3m calculate the maximum volcity of the motion
R=8x10-3m,f=50hz w=2nf=2nx 50=100n=3/4.2rads v=wl =314.2x8x6 =2.513 =2.5lm/s.
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To calculate the maximum velocity of the simple harmonic motion, we can use the formula:
Vmax = 2πfA
Where:
Vmax = Maximum Velocity
f = Frequency
A = Amplitude
Given:
f = 50 Hz
A = 8.0 × 10^(-3) m
Substituting these values into the formula, we get:
Vmax = 2π × 50 × (8.0 × 10^(-3))
Calculating this value, we get:
Vmax ≈ 0.251 m/s
Therefore, the maximum velocity of the motion is approximately 0.251 m/s.
To calculate the maximum velocity of a particle in simple harmonic motion, we can use the equation:
v_max = 2πfA
Where:
v_max is the maximum velocity,
f is the frequency of the motion, and
A is the amplitude of the motion.
In this case, the given values are:
f = 50 Hz
A = 8.0 * 10^(-3) m
Substituting the values into the equation, we have:
v_max = 2π * 50 * 8.0 * 10^(-3)
Now, let's multiply the values:
v_max = 2 * 3.14159 * 50 * 8.0 * 10^(-3)
Simplifying further:
v_max = 3.14159 * 1000 * 8.0 * 10^(-3)
v_max = 3.14159 * 8
v_max ≈ 25.12 m/s
Therefore, the maximum velocity of the particle in simple harmonic motion is approximately 25.12 m/s.