A 5.87-N force is applied (Fapp) to a 2.03-kg object to accelerate it rightwards. The object encounters 3.19-N of friction (Ff). Determine the acceleration (a) of the object.
To determine the acceleration (a) of the object, we can use Newton's second law of motion, which states that the net force (Fnet) acting on an object is equal to the product of its mass (m) and acceleration (a).
First, let's calculate the net force acting on the object. The net force (Fnet) is the difference between the applied force (Fapp) and the force of friction (Ff).
Fnet = Fapp - Ff
Given:
Applied force (Fapp) = 5.87 N
Force of friction (Ff) = 3.19 N
Substituting the given values into the equation, we have:
Fnet = 5.87 N - 3.19 N
Fnet = 2.68 N
Now, we can use Newton's second law to find the acceleration (a) of the object. Rearranging the formula, we have:
Fnet = m * a
Substituting the known values, we get:
2.68 N = 2.03 kg * a
Now, divide both sides by 2.03 kg to solve for a:
a = 2.68 N / 2.03 kg
a ≈ 1.32 m/s²
Therefore, the acceleration (a) of the object is approximately 1.32 m/s².