How many moles of H2 are needed to react completely with 0.25 moles N2 ?
if your reaction is
3H2 + N2 = 2NH3 then you need 3 times as much H2.
There are other possible reactions, though
To answer this question, we need to refer to the balanced chemical equation for the reaction between H2 and N2. The balanced equation is:
N2 + 3H2 -> 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2. Therefore,
1 mole N2 requires 3 moles H2.
Given that we have 0.25 moles of N2, we can calculate the number of moles of H2 needed as follows:
0.25 moles N2 * 3 moles H2 / 1 mole N2 = 0.75 moles H2
So, 0.75 moles of H2 are needed to react completely with 0.25 moles of N2.
To determine how many moles of H2 are needed to react completely with 0.25 moles of N2, we need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction can provide us with this information.
The balanced equation for the reaction between hydrogen gas (H2) and nitrogen gas (N2) is:
N2 + 3H2 → 2NH3
From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
Using this stoichiometry, we can set up a ratio to calculate the number of moles of H2 needed. Since we have 0.25 moles of N2, we can use the mole ratio:
(0.25 moles N2) x (3 moles H2 / 1 mole N2) = 0.75 moles H2
Therefore, 0.75 moles of H2 are needed to react completely with 0.25 moles of N2.