If 12.5 g of Zinc reacts with excess hydrochloric aid, how many grams of zinc chloride are produced?
So,
We have a balanced equation of:
Zn + 2HCL --> ZnCl2 + 2H
Zn is the limiting reactant.
g ZnCl2 = (12.5 g Zn) (1 mole Zn/65.39g) (1 mole ZnCl2/1 mole Zn) (136.29 g ZnCl2 /1 mol) = 26.05 or 26.1 grams, rounded to one sig fig.
To determine the number of grams of zinc chloride produced, we need to calculate the molar mass of zinc chloride (ZnCl2) and convert the given mass of zinc (Zn) into moles. Then, we can use the balanced chemical equation to determine the stoichiometric ratio between zinc and zinc chloride. Finally, the moles of zinc chloride can be converted back to grams.
The molar mass of zinc chloride (ZnCl2) is calculated as follows:
Zinc (Zn) has a molar mass of 65.38 g/mol.
Chlorine (Cl) has a molar mass of 35.45 g/mol (since there are two chlorine atoms in zinc chloride, we multiply this by 2).
So, the molar mass of zinc chloride (ZnCl2) is:
Molar mass = (Molar mass of Zn) + 2 * (Molar mass of Cl)
Molar mass = 65.38 + 2 * 35.45
Molar mass = 136.28 g/mol
Next, we convert the given mass of zinc into moles using the molar mass of zinc:
Moles of zinc = Mass of zinc / Molar mass of zinc
Moles of zinc = 12.5 g / 65.38 g/mol
Moles of zinc = 0.191 moles
From the balanced chemical equation, we can see that the stoichiometric ratio between zinc and zinc chloride is 1:1. This means that for every 1 mole of zinc, 1 mole of zinc chloride is produced.
Therefore, the number of moles of zinc chloride produced is also 0.191 moles.
Finally, we can convert moles of zinc chloride back into grams using the molar mass of zinc chloride:
Mass of zinc chloride = Moles of zinc chloride * Molar mass of zinc chloride
Mass of zinc chloride = 0.191 moles * 136.28 g/mol
Mass of zinc chloride = 26.05 g
Therefore, 12.5 g of zinc reacts with excess hydrochloric acid to produce 26.05 g of zinc chloride.
To determine the number of grams of zinc chloride produced, we need to first balance the chemical equation for the reaction between zinc and hydrochloric acid:
Zn + 2HCl → ZnCl2 + H2
From the balanced equation, we see that one mole of zinc (Zn) reacts with two moles of hydrochloric acid (HCl) to produce one mole of zinc chloride (ZnCl2). We need to use this information to calculate the amount of zinc chloride produced.
Step 1: Convert the mass of zinc (in grams) to moles.
To convert grams to moles, we need to divide the mass by the molar mass of zinc. The molar mass of zinc (Zn) is 65.38 g/mol.
Moles of zinc = Mass of zinc / Molar mass of zinc
In this case, Moles of zinc = 12.5 g / 65.38 g/mol = 0.191 moles of zinc
Step 2: Use the stoichiometry of the balanced equation to find the moles of zinc chloride produced.
From the balanced equation, we know that the molar ratio of zinc to zinc chloride is 1:1. Therefore, the moles of zinc chloride produced is also 0.191 moles.
Step 3: Convert the moles of zinc chloride to grams.
To convert moles of zinc chloride to grams, we multiply the moles by the molar mass of zinc chloride. The molar mass of zinc chloride (ZnCl2) is 136.30 g/mol.
Mass of zinc chloride = Moles of zinc chloride * Molar mass of zinc chloride
In this case, Mass of zinc chloride = 0.191 moles * 136.30 g/mol = 26.07 grams of zinc chloride
Therefore, 12.5 grams of zinc will produce 26.07 grams of zinc chloride when reacted with excess hydrochloric acid.