A = 2πrh + 2πr^2
Solve for H
Perhaps you mean h ?
A - 2 π r^2 = 2 pi r h
(A - 2 π r^2) / 2 pi r = h
or
h = [A/(2 pi r)] - r
To solve for H in the equation A = 2πrh + 2πr^2:
Step 1: Start with the equation A = 2πrh + 2πr^2.
Step 2: Subtract 2πr^2 from both sides of the equation to isolate the term with H. This gives us A - 2πr^2 = 2πrh.
Step 3: Divide both sides of the equation by 2πr to solve for H. This gives us (A - 2πr^2) / (2πr) = h.
Therefore, the equation for H is h = (A - 2πr^2) / (2πr).
To solve for h, we need to isolate it on one side of the equation. Let's go step by step:
1. Start with the equation: A = 2πrh + 2πr^2.
2. Factor out h on the right side of the equation: A = h(2πr) + 2πr^2.
3. Subtract 2πr^2 from both sides of the equation: A - 2πr^2 = h(2πr).
4. Divide both sides of the equation by 2πr to isolate h: (A - 2πr^2) / (2πr) = h.
5. Simplify the expression on the left side: h = (A - 2πr^2) / (2πr).
And there you have it, the equation h = (A - 2πr^2) / (2πr) gives you the value of h in terms of A and r.