Does anyone have the answers for 7th grade math Lesson 13 Unit 1: Percents Unit Test
Which tool can you use to look up the definition of a key word?
A.
spiral review
B.
objectives
C.
glossary
D.
quick check
Kwon records the low temperatures in degrees Celsius on 10 consecutive days. His dataset includes the following numbers: 18,16,21,10,10,15,12,20,17,11
Kwon uses the template below to create a histogram with the bins as shown.
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10. 14. 18. 22
Which bar will be the highest? Identify the range for the correct bar.
The range for each bar is:
- 10 to < 14
- 14 to < 18
- 18 to < 22
To create a histogram, we need to count the frequency of data points in each range and plot the frequency as the height of each bar.
The data points in each range are:
- 10 to < 14: 2 (10, 10)
- 14 to < 18: 4 (16, 15, 12, 17)
- 18 to < 22: 4 (18, 21, 20, 11)
So the bar for the range 14 to < 18 will be the highest, with a frequency of 4.
Loren’s friend jump as far as they can and record their results in inches. Their results include the observations 42,47,50,42,45,41,49,51,and 44. Which number, if I added to the dataset, would represent an outlier in the data? The answer choices are 72,52,44, and 40
To identify an outlier, we need to first find the median (middle value) and the interquartile range (IQR) of the dataset.
Arranging the numbers in order from smallest to largest, we get: 41, 42, 42, 44, 45, 47, 49, 50, 51.
The median is the middle value, which is 45.
To find the IQR, we first need to find the first quartile (Q1) and the third quartile (Q3).
Q1 is the median of the lower half of the dataset, which is 42.
Q3 is the median of the upper half of the dataset, which is 50.
So, IQR = Q3 - Q1 = 50 - 42 = 8.
Any number that is more than 1.5 times the IQR above Q3 (i.e., Q3 + 1.5 x IQR) or below Q1 (i.e., Q1 - 1.5 x IQR) is considered an outlier.
Q3 + 1.5 x IQR = 50 + 1.5 x 8 = 62
Q1 - 1.5 x IQR = 42 - 1.5 x 8 = 30
So, any number that is greater than 62 or less than 30 would be an outlier.
Out of the given answer choices, the number 72 is greater than 62 and would therefore be an outlier in the dataset.
What are the values of the mean, median, and spread for the dataset shown in the bar graph? The bar graph: 10 is at 2 11 is at 4 12 is at 4 and 13 is at 2
To find the mean, we need to multiply each value in the dataset by its frequency, add up these products, and divide by the total frequency. Since the total frequency is 2 + 4 + 4 + 2 = 12, we have:
Mean = (10x2 + 11x4 + 12x4 + 13x2)/12 = 352/12 = 29.33
To find the median, we need to order the values in the dataset from lowest to highest and then find the middle value.
The ordered dataset is: 10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13.
Since there are 12 values in the dataset, the median is the average of the 6th and 7th values, which are both 12 in this case.
Median = (12 + 12)/2 = 12
To find the spread, we can use the range of the dataset, which is the difference between the highest and lowest values.
The lowest value is 10 and the highest value is 13, so:
Spread = 13 - 10 = 3
Therefore, the values of the mean, median, and spread for the given dataset are:
Mean = 29.33
Median = 12
Spread = 3
Find the mean and median for the pat weeks temperatures.
Day of the week Temperature
Sunday. 45 degrees
Monday. 52 degrees
Tuesday 44 degrees
Wednesday. 62 degrees
Thursday. 55 degrees
Friday. 49 degrees
Saturday 50 degrees
To find the mean, we need to add up all the temperatures and divide by the number of days (7):
Mean = (45 + 52 + 44 + 62 + 55 + 49 + 50)/7 = 357/7 = 51 degrees
So the mean temperature for the week is 51 degrees.
To find the median, we need to order the temperatures from lowest to highest:
44, 45, 49, 50, 52, 55, 62
The middle value is the median. Since there are an odd number of values, the median is the fourth value, which is 50.
So the median temperature for the week is 50 degrees.
What value, the mean or median best describes the shape of the data set that contains the number of free throws made by the basket ball team? Choose 1 for mean and 2 for median
Game. Free throws made
1. 4
2. 14
3. 5
4. 7
5. 19
6. 15
7. 6