The product of two numbers is 12. The quotient of the two numbers is 3. What are the two numbers?
idk
4
To find the two numbers, we can set up a system of equations based on the information given.
Let's call the two numbers x and y.
Given that the product of two numbers is 12, we can write the equation as:
x * y = 12 -- (Equation 1)
Given that the quotient of the two numbers is 3, we can write the equation as:
x / y = 3 -- (Equation 2)
To solve the system of equations, we can use the method of substitution.
From Equation 2, we can solve for x:
x = 3y -- (Equation 3, obtained by multiplying both sides of Equation 2 by y)
Now, substitute the value of x from Equation 3 into Equation 1:
(3y) * y = 12
Simplify the left side of the equation:
3y^2 = 12
Divide both sides of the equation by 3:
y^2 = 4
Find the square root of both sides:
y = ±2
Now that we have the value of y, we can find the corresponding value of x by substituting y back into Equation 3:
x = 3y = 3(±2) = ±6
Therefore, the two possible pairs of numbers are (6, 2) and (-6, -2).
The answer would be 9, do the math urself bozos
6*2 = 12
6/2 = 3
xy = 12
x / y = 3