Question

3log2+log20_log1.6

Answer 1

assuming you meant "-" instead of _, we have

3 log2 + log20 - log1.6
= 3 log2 + log2+log10 - log(16/10)
= 3log2 + log2 + 1 - log16 + log10
= 3log2 + log2 + 1 - 4log2 + 1
= 2

check
2^3*20/1.6 = 160/1.6 = 100
log100 = 2