For an arithmetical sequence, the first term is 2 and the common difference is 3. Find the sum of the 11 terms of the sequence.
f1=2, d=3
sum=n/2[2a+(n-1)d]
=11/2[2x2+(11-1)3]
=11/2[4+10x3]
= 11/2[34] = 11x17 =187
I dont really understand
Thanks but f represent what
To find the sum of the terms in an arithmetic sequence, you can use the formula for the sum of an arithmetic series.
The formula for the sum of an arithmetic series is:
S = n/2 * (2a + (n-1)d)
Where:
S is the sum of the series
n is the number of terms in the series
a is the first term of the series
d is the common difference of the series
In this case, the first term (a) is 2, the common difference (d) is 3, and we want to find the sum of 11 terms (n = 11).
Using the formula, we can substitute the values:
S = 11/2 * (2(2) + (11-1)(3))
Simplifying further:
S = 11/2 * (4 + 10(3))
S = 11/2 * (4 + 30)
S = 11/2 * 34
S = 11 * 17
S = 187
Therefore, the sum of the 11 terms in the arithmetic sequence is 187.