Find the most general antiderivative of f(x)=−4x+6(1−x^2)^−1/2, where −1<x<1.
since d/dx arcsin(x) = 1/√(1-x^2)
∫ -4x + 6/√(1-x^2) dx = -2x^2 + 6arcsin(x) + C
Looks like you need to review some of the standard forms.
∫ -4x + 6/√(1-x^2) dx = -2x^2 + 6arcsin(x) + C
Looks like you need to review some of the standard forms.