What is the value of k if the three numbers k+3,2k+6,8 are three consecutive term of an a.p
having a common difference means that
(2k+6) - (k+3) = 8 - (2k+6)
Now work your magic
What is value of k if the three numbers k+3,2k+6,8 are three consecutive term of an a.p
Help me out
To find the value of k, we need to use the concept of an arithmetic progression (AP), where the difference between consecutive terms is constant.
In this case, the three numbers k+3, 2k+6, and 8 form an arithmetic progression. Let's determine the common difference (d) between the terms.
The common difference (d) is given by the formula:
d = second term - first term
Using this formula, we can find the common difference:
d = (2k+6) - (k+3)
d = 2k + 6 - k - 3
d = k + 3
Since d is the common difference, it should be constant for an arithmetic progression.
Now, let's check if the third term, 8, satisfies this condition:
8 = (2k+6) + (k+3)
8 = 3k + 9
To solve this equation for k, we need to isolate k on one side of the equation:
8 - 9 = 3k
-1 = 3k
k = -1/3
Therefore, the value of k is -1/3.