The librarian has 94 books to organize. He wants to put 5 books on some shelves and 6 books on other shelves. How could he arrange the books?
A. Have 8 shelves of 5 books, and 9 shelves of 6 books.
B. Have 9 shelves of 5 books, and 8 shelves of 6 books.
C. Have 5 shelves of 6 books, and 6 shelves of 5 books.
D. Have 7 shelves of 5 books, and 6 shelves of 6 books.
To solve this problem, we need to find a combination of shelves that can accommodate all 94 books. Let's analyze the given options:
Option A suggests having 8 shelves with 5 books each (8 x 5 = 40 books) and 9 shelves with 6 books each (9 x 6 = 54 books). However, 40 + 54 = 94, which is not the desired result.
Option B suggests having 9 shelves with 5 books each (9 x 5 = 45 books) and 8 shelves with 6 books each (8 x 6 = 48 books). Again, 45 + 48 = 93, not the desired result.
Option C suggests having 5 shelves with 6 books each (5 x 6 = 30 books) and 6 shelves with 5 books each (6 x 5 = 30 books). Here, 30 + 30 = 60, which is not sufficient to store all the books.
Option D suggests having 7 shelves with 5 books each (7 x 5 = 35 books) and 6 shelves with 6 books each (6 x 6 = 36 books). When we add these, 35 + 36 = 71, which is still not the desired result.
Therefore, none of the given options can hold all 94 books. The librarian needs to consider alternate arrangements that can accommodate all the books.