There commercials are played in a row between songs on the radio. The three commercials fill exactly 3 minutes of time. If the first commercial uses 1 1/6 minutes, and the second uses 3/5 minute, how long is the third commercial?

A. 23/30 minute

B. 1 23/30 minutes

C. 1 7/30 minutes

D. 2 7/30 minutes

1 1/6 + 3/5 = 1 5/30 + 18/30 = 1 23/30

Answer is D

To find the length of the third commercial, we first need to determine the total time used by the first two commercials.

The first commercial uses 1 and 1/6 minutes, which is the same as 6/6 and 1/6 minutes.
The second commercial uses 3/5 minute.

To find the total time used by the first two commercials, we add the lengths together:

6/6 + 1/6 + 3/5
= 7/6 + 3/5

To add these fractions, we need to find a common denominator. In this case, the least common denominator (LCD) is 30.

Multiplying the fractions by the appropriate factors to get the LCD:

(7/6) * (5/5) + (3/5) * (6/6)
= 35/30 + 18/30

Adding the fractions:

35/30 + 18/30
= 53/30

Therefore, the total time used by the first two commercials is 53/30 minutes.

Since the total time used by the three commercials is 3 minutes, we can find the length of the third commercial by subtracting the total time used by the first two commercials from 3:

3 - 53/30

To subtract fractions, we need a common denominator. The LCD in this case is still 30.

(3/1) - (53/30)
= (90/30) - (53/30)
= 37/30

So the length of the third commercial is 37/30 minutes.

Therefore, the answer is D. 2 7/30 minutes.

To find out the length of the third commercial, we need to subtract the time taken by the first and second commercials from the total time of 3 minutes.

First, let's convert the time taken by the first commercial, which is 1 1/6 minutes, into an improper fraction. We know that 1 whole minute is equal to 6/6, so we can rewrite 1 as 6/6. Therefore, the first commercial takes (6/6 + 1/6) minutes, which simplifies to 7/6 minutes.

Next, let's convert the time taken by the second commercial, which is 3/5 minute, into a common denominator with the first commercial. The common denominator is 30, so we multiply both the numerator and denominator of 3/5 by 6 to get 18/30. Therefore, the second commercial takes 18/30 minutes.

Now, we can subtract the time taken by the first and second commercials from the total time of 3 minutes:

3 - (7/6 + 18/30)

To simplify this calculation, we need to find a common denominator between 6 and 30, which is 30.

Converting the fraction 7/6 to a fraction with a denominator of 30 gives us (35/30).

Now, we have:

3 - (35/30 + 18/30)

Combining the fractions inside the parentheses:

3 - (53/30)

To subtract fractions, we need to have a common denominator. In this case, it is 30. Let's bring 3 to a fraction with 30 as the denominator. 3 is equivalent to (90/30).

Therefore, we have:

(90/30) - (53/30)

Subtracting the fractions:

(90 - 53)/30 = 37/30

So, the length of the third commercial is 37/30 minutes.

In mixed number form, 37/30 can be written as 1 7/30.

Therefore, the answer is C. 1 7/30 minutes.