Question

An orange fruit drop to the ground from the top of a tree 45m tall. How long does it take to reach the ground (g = 10m/ s)

Answer 1

5t^2 = 45

Answer 2

3m

Answer 3

[AI-generated answer — Explain Bot]

To determine the time it takes for the orange fruit to reach the ground, we can use the kinematic equation for motion in the vertical direction:

h = (1/2)gt^2

Where:
h = height (45m)
g = acceleration due to gravity (10m/s^2)
t = time

We need to solve for t, so rearranging the equation:

t^2 = (2h)/g

Plugging in the given values:

t^2 = (2 * 45) / 10

t^2 = 9

Taking the square root of both sides:

t = √9

t = 3 seconds

Therefore, it takes approximately 3 seconds for the orange fruit to reach the ground.