Express the force F3 as Cartesian vector.
ndrewkim.x10host.com/Spring2021/ENGR2605SEC004/CW_CH2/images/figure2.jpg
I think Fx is 4/600 and Fy is 3/600. Am I right?
I forgot that the arrow is pointing downward so Fy= -3/600. Amm I right?
To express the force F3 as a Cartesian vector, we need to determine its components in the x, y, and z directions. From the given image, it is clear that the force F3 has a magnitude of 10 units and is acting at an angle of 30 degrees with the positive x-axis.
To find the x-component of F3, we need to calculate the projection of F3 onto the x-axis. Using trigonometry, we can determine that the x-component (Fx) is given by:
Fx = F3 * cos(theta)
where F3 is the magnitude of the force (10 units) and theta is the angle between F3 and the positive x-axis (30 degrees). Plugging in the values, we get:
Fx = 10 * cos(30)
= 10 * (√3 / 2)
= 5√3 units
Therefore, the x-component of F3 is 5√3 units.
To find the y-component of F3, we need to calculate the projection of F3 onto the y-axis. Again using trigonometry, we can determine that the y-component (Fy) is given by:
Fy = F3 * sin(theta)
where F3 is the magnitude of the force (10 units) and theta is the angle between F3 and the positive x-axis (30 degrees). Plugging in the values, we get:
Fy = 10 * sin(30)
= 10 * (1 / 2)
= 5 units
Therefore, the y-component of F3 is 5 units.
Since there is no information provided about the z-component of F3, it is assumed to be zero. Therefore, the Cartesian vector form of F3 is:
F3 = (5√3, 5, 0)