The sum of a number times 6 and 24 is at most -25
n * 6 + 24 </= -25
6 n </= -49
n </= -49/6
6 n + 24 ≤ -25
To solve this problem, we need to create an inequality equation and find the range of values for the number. Let's call the number "x".
The sum of a number times 6 and 24 can be expressed as "6x + 24".
According to the problem, this sum is at most -25. So we can write the inequality as:
6x + 24 ≤ -25
To solve the inequality, we need to isolate the variable "x". Let's start by subtracting 24 from both sides of the inequality:
6x + 24 - 24 ≤ -25 - 24
6x ≤ -49
Next, we divide both sides of the inequality by 6 to isolate "x":
(6x)/6 ≤ (-49)/6
x ≤ -49/6
Therefore, the solution to the inequality is x ≤ -49/6.
In summary, the range of values for the number "x" is any value less than or equal to -49/6.