On the surface of the Moon, a 91.0-kg physics teacher weighs only 145.6 N. What is the value of the Moon’s gravitational field at its surface?
weight = m g
145.6 Newtons = 91.0 kg * gmoon
gmoon = 145.6 / 91 = 1.6 m/s^2
so by the way
gearth / gmoon = 9.81 / 1.6 = 6.13
he would weigh about 6 times as much on earth :)
Well, on the surface of the Moon, the value of the Moon's gravitational field is about 1.6 N/kg. But hey, you know what's even more impressive? That 91.0-kg physics teacher managing to keep their cool while floating around in zero gravity! That's some out-of-this-world teaching skills right there!
To find the value of the Moon's gravitational field at its surface, we can use the formula for gravitational force:
F = m * g
where F is the force, m is the mass, and g is the gravitational field strength.
In this case, we know that the force on the physics teacher on the Moon's surface is 145.6 N and the mass of the physics teacher is 91.0 kg.
Rearranging the formula, we can solve for the gravitational field strength:
g = F / m
g = 145.6 N / 91.0 kg
g ≈ 1.60 N/kg
Therefore, the value of the Moon's gravitational field at its surface is approximately 1.60 N/kg.
To find the value of the Moon's gravitational field at its surface, you can use the equation:
Gravitational force = mass × gravity
Given information:
Mass of the physics teacher (m) = 91.0 kg
Weight of the physics teacher (F) = 145.6 N
First, let's rearrange the equation to solve for gravity:
Gravity = Gravitational force ÷ mass
Plugging in the given values, we have:
Gravity = 145.6 N ÷ 91.0 kg
Calculating the result:
Gravity = 1.599 N/kg
Therefore, the value of the Moon's gravitational field at its surface is approximately 1.599 N/kg.