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The magnitude of the velocity of a car is given by the equation v=|35t-70| where t represents time in seconds and v represents velocity in meters per second. Algebraically determine when the magnitude of velocity is 17.5 m/s.

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impatient much?

see your previous post.

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In algebra, you can use equations to determine the magnitude of an object's velocity. The equation v=|35t-70| represents the magnitude of the velocity of a car, where t is time in seconds and v is velocity in meters per second. To find when the magnitude of velocity is 17.5 m/s, we can set the equation equal to 17.5 and solve for t. Starting with the equation v=|35t-70|, we substitute 17.5 for v: 17.5 = |35t-70| Next, we isolate the absolute value expression by splitting it into two cases: Case 1: 35t-70 is positive: 17.5 = 35t-70 Adding 70 to both sides of the equation, we get: 87.5 = 35t Dividing both sides by 35, we find: t = 2.5 Case 2: 35t-70 is negative: 17.5 = -(35t-70) Expanding the negative sign inside the absolute value, we have: 17.5 = -35t + 70 Subtracting 70 from both sides of the equation, we obtain: -52.5 = -35t Dividing both sides by -35, we get: t = 1.5 Therefore, when the magnitude of velocity is 17.5 m/s, it can occur at either t = 1.5 seconds or t = 2.5 seconds.