The boys and girls soccer clubs are trying to raise money for new uniforms. The boy's soccer club is selling candy bars for $2 and the girl's soccer club is selling boxes of cookies for $3. They must raise $1000
A. if b represents the number of cany bars and c represents the number of boxes of cookies, determine an inequality that models the combinations of candy bar and boxes of cookies that meets the fundraising goal.
B.State 2 possible combinations of sales that will raise more than $1000
please show steps and answer again for the same review if you can. I think this is my last question, I might have one more, but thank you so much Mr Oobleck you've been a lot of help latley
2 b = candy bar income
3 c = cookie income
so
2 b + 3 c >/= $1,000
LOL 500 bars OR 334 cookie boxes
A. To model the combinations of candy bars and boxes of cookies that meet the fundraising goal of $1000, we need to consider the total revenue obtained from selling candy bars and boxes of cookies.
Let's assign variables to represent the number of candy bars (b) and the number of boxes of cookies (c) sold. The revenue from selling candy bars would be $2 times the number of candy bars (2b), and the revenue from selling boxes of cookies would be $3 times the number of boxes of cookies (3c). To meet the fundraising goal, the total revenue should be greater than or equal to $1000. Therefore, the inequality representing the combinations would be:
2b + 3c ≥ 1000
B. To find two possible combinations of sales that will raise more than $1000, we need to look for values of b and c that satisfy the inequality mentioned above. Here are two possible combinations:
Combination 1: Let's assume the boys' soccer club sells 400 candy bars (b = 400) and the girls' soccer club sells 200 boxes of cookies (c = 200). Plugging these values into the inequality:
2b + 3c = 2(400) + 3(200) = 800 + 600 = 1400
Since 1400 is greater than 1000, this combination raises more than $1000.
Combination 2: Let's assume the boys' soccer club sells 300 candy bars (b = 300) and the girls' soccer club sells 250 boxes of cookies (c = 250). Plugging these values into the inequality:
2b + 3c = 2(300) + 3(250) = 600 + 750 = 1350
Since 1350 is also greater than 1000, this combination raises more than $1000.
Please note that these are just two possible combinations, and there could be other combinations that raise more than $1000 as well.