Hello, my question is: How do I determine the molar ratio of zinc to oxygen in the compound and write its formula?

I have 36.06 g of Zn heated in an open crucible. It reacts with oxygen in the air to make a product with a mass of 44.8 g.

I figured out how many moles there are present in each product.
Zinc = 0.552 moles
Oxygen = 0.545 moles

What would I do to determine the molar ratio?
So far I have:
Zn + O2 ---> ZnO2

What do I then do to find the molar ratio of zinc to oxygen and its formula?

I have 36.06 g of Zn heated in an open crucible. It reacts with oxygen in the air to make a product with a mass of 44.8 g.

36.06 g * 1 mol /65.38 g = 0.552 mol of Zn

44.8 - 36.06 = 8.74 g of O
O is 16 g/mol
so
8.74 g * 1 mol / 16 g = 0.546 mol of O
Looks like ZnO one mol zinc to one mol O
2 Zn + O2 ---> 2 ZnO

How did you end up with 2 ration id it only gives you one?

Shouldnt be Zn+O=ZnO?

To determine the molar ratio of zinc to oxygen in the compound and write its formula, you need to compare the number of moles of each element present in the compound.

From your calculations, you found that the number of moles of zinc (Zn) is 0.552 moles, and the number of moles of oxygen (O) is 0.545 moles.

Since we want to find the simplest ratio between the two elements, we need to divide the number of moles of each element by the smaller number of moles. In this case, we divide both 0.552 and 0.545 by 0.545.

0.552 moles Zn divided by 0.545 moles O = 1.014
0.545 moles O divided by 0.545 moles O = 1

Now, we have ratios of approximately:
Zn:O = 1.014:1

To simplify this ratio, you can multiply both sides by 100 to get whole numbers:
101.4:100

Therefore, the molar ratio of zinc to oxygen in the compound is 101.4:100, or approximately 101:100.

To write the formula of the compound, you need to use the molar ratio. Since the ratio is close to 1:1, this suggests a 1:1 ratio of zinc to oxygen in the compound.

Hence, the formula of the compound is ZnO.

To determine the molar ratio of zinc to oxygen in the compound and write its formula, you need to use the balanced chemical equation and the moles of each element you calculated.

From the given information, you have 0.552 moles of zinc and 0.545 moles of oxygen. The balanced chemical equation you provided, Zn + O2 ---> ZnO2, suggests that the formula of the compound is ZnO2. However, this equation seems incorrect.

To determine the correct molar ratio, we need to balance the chemical equation. Let's assume the balanced equation is:

2Zn + O2 ---> 2ZnO

Now, we can see that for every 2 moles of zinc (Zn) reacting, we have 1 mole of oxygen (O2) reacting to form 2 moles of zinc oxide (ZnO).

Therefore, the molar ratio of zinc to oxygen is 2:1, meaning that for every 2 moles of zinc, we have 1 mole of oxygen.

The correct formula based on the balanced equation is ZnO.