What is the distance between the points (-4, -6) and (8, -10)? Round the answer to the nearest tenth.
distance = √[(x1 - x2)^2 + (y1 - y2)^2]
To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Let's apply this formula to find the distance between the points (-4, -6) and (8, -10).
x1 = -4 (x-coordinate of the first point)
y1 = -6 (y-coordinate of the first point)
x2 = 8 (x-coordinate of the second point)
y2 = -10 (y-coordinate of the second point)
Substituting these values into the formula, we get:
d = √((8 - (-4))^2 + (-10 - (-6))^2)
Simplifying further:
d = √((8 + 4)^2 + (-10 + 6)^2)
d = √(12^2 + (-4)^2)
d = √(144 + 16)
d = √160
To round the answer to the nearest tenth, we can evaluate √160 approximately.
Using a calculator:
d ≈ 12.65
So, the distance between the points (-4, -6) and (8, -10) rounded to the nearest tenth is approximately 12.65 units.